Answer:
The correct answer is 175 grams of Chlorine is required.
Step-by-step explanation:
The reaction for the given case is:
TiO₂ (1 mole) + 2Cl₂ (2 mole) → TiCl₄ + O₂
From the reaction, it can be observed that 1 mole of TiO₂ reacts with 2 mole of Cl₂ to produce 1 mole of TiCl₄.
Therefore, 1.25 mole of TiO₂ will react with 2.5 mole of Cl₂ to produce 1 mole of TiCl₄.
The molecular weight of 1 mole of Cl₂ is 70 g
Thus, 2.5 mole of Cl₂ = 70 × 2.5 = 175 g
Therefore, for complete reaction of 1.25 mole of TiO₂, 175 g of Cl₂ will be needed.