Answer:
51.88 kJ / g
Solution:
As we know 1 mole of ethane equals 30.07 g as,
C₂H₆ = (12.01)₂ + (1.008)₆
= 24.02 + 6.048
1 mole = 30.068 g
Now, As heat of combustion of ethane C₂H₆ is,
= 1560 kJ / mol
Substituting value of mole by gram,
= 1560 kJ / 30.068 g
= 51.88 kJ / g