Question

An electron is ejected at a speed of 1.7*10^6 m/s from the electron gun of a computer monitor. If the viewing screen is 32 cm from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

Answer 1

Using the equation
S = vt
time taken to reach screen = s/v
t = 0.32/1.7 × 10^6
t = 1.882 × 10^-7 sec
Distance fallen due to gravity in this time will be;
S = 0.5 gt²
= 0.5 × 9.91 ×(1.882 × 10^-7)²
= 9.325 × 10^-14 m