Question

2^X = 17^X

How do you solve that equation?

Answer 1

For this case we must solve the following equation:

`2 ^ x = 17 ^ x`

For this, we follow the steps below:

We find the Neperian logarithm on both sides of the equation to remove the variable from the exponent

`ln (2 ^ x) = ln (17 ^ x)`

We use one of the logarithm properties to extract x from the exponent:

`xln (2) = xln (7)`

We subtract xln (7) on both sides of the equation:

`xln (2) -xln (7) = 0`

We take x common factor:

`x (ln (2) -ln (7)) = 0`

We divide between
`(ln (2) -ln (7))`on both sides of the equation, then:

`x = 0`

Answer:

`x = 0`