Question

Mona is skating at a speed of 300 feet per minute. Lina is 1000 feet behind her. What should be her speed if she wants to catch up with Mona in 10 minutes?

Answer 1

If we translate the facts into location equations, xM=Mona's location, xL=Lina's location, then we get:

xM(t) = 300t
xL(t) = v*t - 1000
xM(10)=xL(10)

Where v is Lina's speed we have to find.

Plugging them all together gives:

300*10 = 10v - 1000

Which can be solved:

3000 + 1000 = 10v
4000 = 10v
v=400

Lina should skate at 400 feet per minute!