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PLEASE HELP! $7600 is invested for one year, part at 4% and the remainder at 5%. The income from the two investments is $338. Find the amount invested at 4%.
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PLEASE HELP!

$7600 is invested for one year, part at 4% and the remainder at 5%. The income from the two investments is $338. Find the amount invested at 4%.

User Bhavya Parikh
by
8.4k points

2 Answers

0 votes

Answer:

4200

Explanation:

User Fotanus
by
8.8k points
2 votes
x is the 4%
y is the 5%

x+y=7600
y=7600-x

0.05y=338-0.04x

5y=33800-4x
y=7600-x

Solve with substitution

5(7600-x)=33800-4x
38000-5x=33800-4x
4200=x

User Wulimaster
by
7.7k points
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