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What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16?
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What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16?

User BernardV
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1 Answer

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2(3y + 6 + 3) = 196
2(3y + 9) = 196
6y + 18 = 196
6y + 18 - 18 = 196 - 18
6y = 178

Divide both sides by 6

y = 178 / 6

y ≈ 29.667
User Brian Rothstein
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