Question

Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)

Answer 1

Standard equation: (x-h)^2 + (y-k)^2 = r^2

Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10

Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2