Question

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.

Answer 1

`C_(x)H_(y) + O_(2) --\ \textgreater \ x CO_(2) + (y)/(2) H{2}O 540mg H_(2)O* (1 mmol H_(2)O)/(18 mg H_(2)O) =30 mmol H_(2)O \\ \\30 mmolH_(2)O -have - 60 mmol H \\ \\ 60 mmol H* (1mg H)/(1 mmol H) =60 mg H \\ \\300mg C_(x)H_(y) - 60 mg H= 240 mg C \\ \\ 240 mgC* (1mmol)/(12mg) =20 mmol C 20 mmol C: 60 mmol H=1 mol C : 3 mol H`