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Two students in different classes took the same math test. Both students received a score of 87. In student A's class the mean was 78 and the standard deviation of 5. In student B's class the mean was 76 with a standard deviation of 4. Which student scored in the top 10% of their class?

A. student b
b. student a
C. both students
D. neither student

User Jeagr
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1 Answer

3 votes

Answer: Student B will score in the top of the class.

Explanation:

Here both the students of class A and B scored 87.

Therefore, the value of random variable for both class is, x = 87

According to the question, mean for the class A is,
\mu_1 = 78

And, standard deviation for class A,
\sigma_1 = 5

Thus, the z-score for Class A,


z_1 = (x-\mu_1)/(\sigma_1)


z_1 = (87-78)/(5) = 9/5 = 1.8

And,
z_1(1.8)=0.9641

Also, mean for the class B is,
\mu_2 = 76

And, standard deviation for class B,
\sigma_2 = 4

Thus, the z-score for Class B,


z_2 = (x-\mu_2)/(\sigma_2)


z_2 = (87-76)/(4) = 11/4 = 2.75


z_2(2.75)=0.9970

Thus,
z_2 > z_1

Therefore, student B scored in the top 10% of their class.



User StyleZ
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