Answer: Student B will score in the top of the class.
Explanation:
Here both the students of class A and B scored 87.
Therefore, the value of random variable for both class is, x = 87
According to the question, mean for the class A is,
![\mu_1 = 78](https://img.qammunity.org/2019/formulas/mathematics/high-school/e6rwqd9rtvl5o16sjsmvzahfipahtepijo.png)
And, standard deviation for class A,
![\sigma_1 = 5](https://img.qammunity.org/2019/formulas/mathematics/high-school/ogznsjjr96hrnl53oda5byvyvr5rpp2vut.png)
Thus, the z-score for Class A,
= 9/5 = 1.8
And,
Also, mean for the class B is,
![\mu_2 = 76](https://img.qammunity.org/2019/formulas/mathematics/high-school/kiqcfkel8afutnba8l2uqtpeny11noavw1.png)
And, standard deviation for class B,
![\sigma_2 = 4](https://img.qammunity.org/2019/formulas/mathematics/high-school/j8pliu13o04rgzjx5xzsfm75j71dvrm0ix.png)
Thus, the z-score for Class B,
= 11/4 = 2.75
Thus,
![z_2 > z_1](https://img.qammunity.org/2019/formulas/mathematics/high-school/1go0dacy68h6p2xga5jrydpw1dn8azx2l9.png)
Therefore, student B scored in the top 10% of their class.