Answer:
y = 0.5 at x = 4
Explanation:
According to question,
y is inversely proportional to cube of x i.e.
![y\propto (1)/(x^3)\\\\y=(k)/(x^3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/vxlkkvimp061wpioq6mloubn0e7whfchyy.png)
or
![k=yx^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/teqdglyep02s3k7ejtk3jvy0dp4etl1mr8.png)
Put x = 2 and y = 4 in above expression to find k.
![k=4* (2)^3\\\\=32](https://img.qammunity.org/2022/formulas/mathematics/high-school/r3mew30m1wlcbvyttw22cwsm6rweceng7j.png)
Now put x = 4 to given equation to find y.
![y=(32)/(4^3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/x3sx0x2chdvf3op84nx7lviszgk21clfg5.png)
y = 0.5 or 1/2
So, the value of y is 0.5 when x = 4.