Question

A rectangle has a perimeter of 34 cm in an area of 52 cm squared it's length is 5 more than twice its width write and solve the system of equations to find the dimensions of the rectangle

Answer 1

L+W=17 W=4 is the answer.

Answer 2

Let
`l` be the length and
`w` be the width of the rectangle.

Given perimeter of the rectangle

`2(l+w)=34 \; l+w=17`

Area of the rectangle is

`lw=52`

Also length is 5 more than twice its width,

`l=2w+5`

From the above equations

`image`

Now
`2l=9+17=26\;,l=13,w=4`

The dimensions of the rectangle are length
`l=13`, and width
`w=4`.