the complete question is
Four golf balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylinder. The diameter of each ball is 4cm.
1) What is the volume of the cylinder rounded to the nearest cubic centimeter?
2) What is the total volume of the four balls rounded to the nearest cubic centimeter?
3) What percent of the volume of the container is occupied by the four balls?
Part 1) volume of the cylinder=pi*r²*h
r=4/2----> 2 cm
h=4*4----> 16 cm
volume of the cylinder=pi*2²*16----> 200.96 cm³----> 201 cm³
the answer Part 1) is 201 cm³
Part 2) volume of a sphere=(4/3)*pi*r³ ( is equal to volume of one golf ball)
r=2 cm
volume of a sphere=(4/3)*pi*2³ ----> 33.49 cm³
so
volume of four golf ball-----> 4*33.49----> 133.97 cm³----> 134 cm³
the answer part 2) is 134 cm³
part 3)
volume of cylinder=201 cm³
volume of the four golf ball=134 cm³
so
if 201 cm³-----------> 100%
134 cm³--------> x
x=134*100/201----> x=66.67%
the answer part 3) is 66.67%