Question

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer 1

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

`v=\sqrt{(T)/((m/l))}`

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

`(m/l)=(10)/(V^2)`

Step-by-step explanation:

From the question we are told that

Speed of a transverse wave given by

`v=\sqrt{(T)/((m/l))}`

Maximum Tension is
`T=10.0N`

Generally making
`(m/l)` subject from the equation mathematically we have

`v=\sqrt{(T)/((m/l))}`

`v^2=(T)/((m/l))`

`(m/l)=(T)/(V^2)`

`(m/l)=(10)/(V^2)`

Therefore the Linear mass in terms of Velocity is given by

`(m/l)=(10)/(V^2)`