Answer:
![(-2p^2+10p-8)/(p^2-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/f7mnq1z90hr8l87hxs8hpabqjfb2sujjow.png)
This can be written as (-2p^2+10p-8)/(p^2-4) on a keyboard.
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Work Shown:
![(2p)/(p^2-4) + (4-2p)/(p+2)\\\\\\(2p)/((p+2)(p-2)) + (4-2p)/(p+2)\\\\\\(2p)/((p+2)(p-2)) + ((4-2p)(p-2))/((p+2)(p-2))\\\\\\(2p+(4-2p)(p-2))/((p+2)(p-2))\\\\\\(2p-2p^2+8p-8)/(p^2-4)\\\\\\(-2p^2+10p-8)/(p^2-4)\\\\\\](https://img.qammunity.org/2022/formulas/mathematics/high-school/srncc5nn64atii5rupnxb1igs75enztbnb.png)
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Explanations:
- In step 2, I factored p^2-4 using the difference of squares rule.
- In step 3, I multiplied top and bottom by (p-2) so that the second fraction has a denominator of (p+2)(p-2). We can only add fractions that have the same denominator.
- In step 5, I used the FOIL rule to expand (4-2p)(p-2) into -2p^2+10p-8. You can use the distribution rule or the box method as alternatives.