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A population of bacteria is growing according to the exponential model P = Cekt, where P is the number of colonies and t is measured in hours. If there are 800 colonies present after 4 hours, and the population's growth rate k = 0.65, how many colonies were present initially? [Round answer to the nearest hundredth.]

User Smargh
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Plugging our values into the equation, we have


800=Ce^(0.65(4)) \\ \\800=Ce^(2.6) \\\text{Dividing both sides by }e^(2.6) \\ \\(800)/(e^(2.6))=C \\ \\59.42=CThe correct answer is 59.42.
User Riskop
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