Question

A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jack picks a fruit at random and does not replace it. Then Bethany picks a fruit at random. What is the probability that Jack gets a peach and Bethany gets an orange?

Answer 1

5/14 × 2/13 = 10/182

simplify by 2

10/182 ÷ 2/2

5/91

5 over 91

Answer 2

Hello!

You have to find the probabilities of them happening separately

To do this you do the amount of favorable outcomes over the total amount of outcomes

3 + 2 + 2 + 2 + 5 = 14 total fruit

The chance of Jack getting a peach is 5 / 14

The chance of Bethany getting an orange is 2 / 13 because Jack did not put the fruit back in so their is one less to choose from

You multiply the two probabilities to find the probability of them happening in a row

5/14 * 2/13 = 5/91

The answer is 5/91

Hope this helps!