Question

Cameron used 1 3/4 ounces of hydrochloric acid in one experiment. She used 2 1/8 ounces of the acid in a second experiment. How much more acid did Cameron use in the second experiment?

Answer 1

3/8ths more
2 1/8 -1 3/4 =
17/8 - 14/8 = 3/8ths

Answer 2

Amount required is
`x=(3)/(8)`

Explanation:

Given : Cameron used
`1(3)/(4)` ounces of hydrochloric acid in one experiment. She used
`2(1)/(8)` ounces of the acid in a second experiment.

To find : How much more acid did Cameron use in the second experiment?

Solution :

In one experiment,

Cameron used
`1(3)/(4)` ounces of hydrochloric acid

i.e
`1(3)/(4)=(7)/(4)`

In second experiment,

She used
`2(1)/(8)` ounces of the acid.

i.e.
`2(1)/(8)=(17)/(8)`

Let x amount more she used then experiment 1 in experiment 2.

So, the equation became

`(7)/(4)+x=(17)/(8)`

`x=(17)/(8)-(7)/(4)`

`x=(17-14)/(8)`

`x=(3)/(8)`

Therefore, Amount required is
`x=(3)/(8)`