Question

The center of the circle whose equation is (x + 1)² + (y + 2)² = 49 is

Answer 1

The center of a circle can be determined by looking at what is being done to x and y.
The formula for a circle is (x-h)^2 =(y-k)^2=r^2 . H is the x coordinate and k is the y coordinate. r is the radius. You have to be careful, though when they throw in the addition. Here is what your equation really looks like:
(x-(-1))^2 +(y-(-2))^2=49. Your center is at (-1,-2) and you have a radius of 7.
Hope that helps!

Answer 2

Answer: (-1, -2)

Explanation:

The general equation of a circle is given by :-

`(x-h)^2+(y-k)^2=r^2`, where (h,k) is center and r is radius of the circle.

Given : The equation of a circle :
`(x+1)^2+(y+2)^2=49`

`\Rightarrow\ (x-(-1))^2+(y-(-2))^2=7^2`

Comparing to the general equation of circle , we get

`(h,k)=(-1, -2)`

Hence, the coordinates of the center of the circle = (-1, -2)