Question

Curious George is whirling a 2.0 kg bunch of bananas on a smooth floor in a circular path having a radius of 0.50 m. What force must he apply to keep the motion constant so that the bananas complete one revolution every 4.0 seconds

Answer 1

The force will be
`F_(c)=2.47 N`

Step-by-step explanation:

Let's use the centripetal force equation.

`F_(c)=m\omega ^(2)R`

Where:

m is the mass of the bunch of bananas

ω is the angular speed

R is the radius

Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.

`\omega =0.25(rev)/(s)=0.25*2\pi (rad)/(s)=1.57 (rad)/(s)`

FInally, the force will be:

`F_(c)=2.0*1.57^(2)*0.5`

`F_(c)=2.0*1.57^(2)*0.5`

`F_(c)=2.47 N`

I hope it helps you!