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What is the inverse of the function f(x)= 19/x^3 ?

User Jsegal
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1 Answer

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f(x)=(19)/(x^3)\to y=(19)/(x^3)\\\\(y)/(1)=(19)/(x^3)\ \ \ \ |cross\ multiply\\\\yx^3=19\ \ \ \ |:y\\eq0\\\\x^3=(19)/(y)\to x=\sqrt[3]{(19)/(y)}
Answer:
f^(-1)(x)=\sqrt[3]{(19)/(x)}

User Sreginogemoh
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