Question

A 720 g softball is traveling at 15.0 m/s when caught. If the force of the glove on the ball is 520 N, what is the time it takes the ball to stop

Answer 1

The time it takes the ball to stop is 0.021 s.

Step-by-step explanation:

Given;

mass of the softball, m = 720 g = 0.72 kg

velocity of the ball, v = 15.0 m/s

applied force, F = 520 N

Apply Newton's second law of motion, to determine the time it takes the ball to stop;

`F = ma = (mv)/(t) \\\\t = (mv)/(F) \\\\t = (0.72 \ * \ 15)/(520) \\\\t = 0.021 \ s \\`

Therefore, the time it takes the ball to stop is 0.021 s.