Answer with explanation:
It is given that ,Marge correctly guessed whether a fair coin turned up "heads" or "tails" on sic consecutive flips.
When we flip a coin , there are two possible Outcomes, one is Head and another one is Tail , that is total of 2.
Probability of an event
![=\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}](https://img.qammunity.org/2019/formulas/mathematics/high-school/inzst7xkc8701as74hjb7em55twag5wtgj.png)
Probability of getting head
![=(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6wjeds0vzwpkzl9zvdgxdvkilxre003d3w.png)
Probability of getting tail
![=(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6wjeds0vzwpkzl9zvdgxdvkilxre003d3w.png)
⇒There can be two guesses , either it will be true and another one will be false.
So, Possible outcome of correct guess={True, False}=2
--Probability of Incorrect(False) guess
![=(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6wjeds0vzwpkzl9zvdgxdvkilxre003d3w.png)
--Probability of Correct(True) guess in seventh toss
![=(1)/(2)\\\\=(1)/(2) * 100\\\\=50 \text{Percent}](https://img.qammunity.org/2019/formulas/mathematics/high-school/wlgc6m6vrrmvdwwr0uwthw3y0c2v4ndxrt.png)
⇒Probability that she will correctly guess the outcome of the Seventh coin toss, if previous sixth tosses has correct guess
=T×T×T×T×T×T×T, where T=True guess
= 0.5×0.5×0.5×0.5×0.5×0.5×0.5
=0.0078125
=0.0078 (approx)