A. Moles of Aluminum needed;
Reaction is as follow,
Fe₂O₃ + 2 Al → 2 Fe + Al₂O₃
According to eq,
1 mole Fe₂O₃ required = 2 mole of Al
So,
3.30 mol Fe₂O₃ will require = X moles of Al
Solving for X,
X = (2 mol × 3.30 mol) ÷ 1 mol
X = 6.6 mol of Al
B. Moles of Iron formed:
According to eq,
1 mole Fe₂O₃ produced = 2 mole of Fe
So,
3.30 mol Fe₂O₃ will produce = X moles of Fe
Solving for X,
X = (2 mol × 3.30 mol) ÷ 1 mol
X = 6.6 mol of Fe
C. Moles of Aluminum Oxide formed:
According to eq,
1 mole Fe₂O₃ produced = 1 mole of Al₂O₃
So,
3.30 mol Fe₂O₃ will produce = X moles of Al₂O₃
Solving for X,
X = (1 mol × 3.30 mol) ÷ 1 mol
X = 3.30 mol of Al₂O₃