Question

consider two point charges of 1.60uC and -22.25uC. Determine the magnitude of the force between the two charges when placed 6.50cm apart.

Answer 1

`F$\approx$76`

Step-by-step explanation:

From the question we are told that

Point charges
`q_1=1.60uC`

`q_2=-22.25uC`

Displacement
`d=6.50cm=>0.065m`

Generally the equation for Coulomb's law is Mathematically given as

`F=(k*q_1*q_2)/(r^2)`

Therefore

`F=(9*10^9*-22.25*10^-^6*(1.60)*10^-^6)/((6.50*10^-^2)^2)`

`F=-75.83431953`

`F$\approx$-76`

with -(negative) showing form of force Magnitude =>
`F$\approx$76`