Question

JK, KL, and LJ are all tangent to circle O. The diagram is not drawn to scale. If JA = 10, AL = 23, and CK = 9, what is the perimeter of ∆JKL

A.84
B.66
C.42
D.38

Answer 1

Answer: the perimeter of JKL is 84

ik this is rlly late but to help anyone else who gets this question:

This is an equilateral triangle, so the adjacent length is gonna be the same value as its corresponding length that was listed

JA = 10

JB = JA, JB is also 10

JA + JB (10+10) = 20

AL = 23

LC = AL, LC is also 23

AL + LC (23+23) = 46

CK = 9

KB = CK, KB is also 9

CK + KB (9+9) = 18

add all those up:

20 + 46 + 18 = 84