Question

At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. what is the volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa?

Answer 1

At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. The volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa is 1.66 L.

Answer 2

V = 1.66 L

Step-by-step explanation:

As we know that at the depth of 10 m the volume of the lungs of diver is given as

V = 2.40 L

Temperature = 32 degree C

Pressure = 101.30 kPa

Now we have change the values of pressure and temperature

Pressure = 141.20 kPa

Temperature = 21 degree C

Now we can use idea gas equation to solve this

`PV = nRT`

`(P_1V_1)/(RT_1) = (P_2V_2)/(RT_2)`

so we have

`(101.30 * 2.40)/(R(273 + 32)) = (141.20 * V)/(R(273 + 21))`

`V = 1.66 L`