PROBABILITY PROBLEM! NEED HELP AND EXPLAIN/SHOW WORK

asked Aug 21, 2019 90.2k views

1 vote

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2 votes

10 + 5 + 1 = 16 - all balls
The probability that the first ball is red:

P(R)=(10)/(16)=(5)/(8)

The probability that the second ball is black:

P(B)=(1)/(15)

Together:

$P(R)\cdot P(B)=(5)/(8)\cdot(1)/(15)=(1)/(24)$

Hector Correa answered Aug 26, 2019

8.2k points

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