We can use the pascal triangle to solve this problem.
For this case, rewriting each binomial we have:
(x + y) ^ 1 = 1x + 1y
(x + y) ^ 2 = 1x ^ 2 + 2xy + 1y ^ 2
(x + y) ^ 3 = 1x ^ 3 + 3x ^ 2y + 3xy ^ 2 + 1y ^ 3
(x + y) ^ 4 = 1x ^ 4 + 4x ^ 3y + 6x ^ 2y ^ 2 + 4xy ^ 3 + 1y4