Question

The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?

A.) (3,4)
B.) (3,5)
C.) (30,401)
D.) (30,501)

Answer 1

The answer is C. (30,401) I already checked. 

Answer 2

For this case we have the following equations that represent the position of the rocket:
x (t) = 3t
y (t) = 4t ^ 2 + 1
Substituting t = 10 in both equations we have:
x (10) = 3 (10) = 30
y (10) = 4 (10) ^ 2 + 1 = 400 + 1 = 401
Therefore, the position of the rocket is:
(x, y) = (30, 401)
Answer:
the ship after 10 seconds is at:
C.) (30,401)