For this case we have the following polynomial:
(4x + 5) (- 3x-1)
Rewriting we have:
-12x ^ 2 - 4x - 15x - 5
-12x ^ 2 - 19x - 5
The equivalent polynomials for this case are given by:
(-16x ^ 2 + 10x - 3) + (4x ^ 2 - 29x - 2)
2 (x - 1) - 3 (4x ^ 2 + 7x + 1)
(2x ^ 2 - 11x - 9) - (14x ^ 2 + 8x - 4)
Answer:
(-16x ^ 2 + 10x - 3) + (4x ^ 2 - 29x - 2)
2 (x - 1) - 3 (4x ^ 2 + 7x + 1)
(2x ^ 2 - 11x - 9) - (14x ^ 2 + 8x - 4)