Question

Help a brother out lol

Answer 1

We know that
`f(x)=3x+1` and
`g(x)=x^2-6`; to find
`( (g)/(f) )(x)` we are going to divide
`g(x)` by
`f(x)`:

`( (g)/(f) )(x)= (x^2-6)/(3x+1)`
Since the denoinatorcan't be zero:

`3x+1 \\eq 0`

`x \\eq - (1)/(3)`

We can conclude that the correct answer is A.
`(x^2-6)/(3x+1)`
`x \\eq - (1)/(3)`