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. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?

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2 votes
Answer:
Four

Step-by-step explanation:
Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,

Ca → Ca²⁺ + 2 e⁻

These two electrons are accepte by Sulfur as,

S + 2 e⁻ → S²⁻

So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,
. how many lone pairs of electrons are present in the lewis structure of calcium sulfide-example-1
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