Question

Calculate the volume in milliliters of a 5.11/mol silver nitrate solution that contains 175.g of silver nitrate AgNO3. Round your answer to 3 significant digits.

Answer 1

`V=202mL`

Step-by-step explanation:

Hello!

In this case, considering we have a 5.11-molar solution (5.11 M) that contains 175. g of silver nitrate, we first need to compute the moles of solute as its molar mass is 169.87 g/mol:

`n=175g*(1mol)/(169.87 g) =1.03mol`

Next, since the definition of molarity is moles over volume:

`M=(n)/(V)`

We solve for the volume and plug in the molarity and moles as shown below:

`V=(n)/(M) =(1.03mol)/(5.11mol/L)\\\\V =0.202L`

However, as it is needed in milliliters, we convert the L to mL:

`V=0.202L*(1000mL)/(1L)\\\\V=202mL`

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