Question

Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)

Answer 1

To get started, combine -4s+4 with 4s - 4. Result: 0. That leaves

2s 4 2(s+2)
------ - ------- = ------------
s^2 s^2 s^2

Answer 2

To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:

`(2s)/(s^2-4s+4) -( (4)/(s^2-4s+4) )`

`(2s)/(s^2-4s+4) -(4)/(s^2-4s+4)= (2s-4)/(s^2-4s+4)`

Now we can factor both numerator and denominator and simplify:

`(2s-4)/(s^2-4s+4) = (2(s-2))/((s-2)^2) = (2)/(s-2)`

We can conclude that the difference in simplest form is:
`(2)/(s-2)`