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Multiply \frac{y^2-9}{-2y} *\frac{-5y}{y+3}

Multiply \frac{y^2-9}{-2y} *\frac{-5y}{y+3}
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Multiply

\frac{y^2-9}{-2y} *\frac{-5y}{y+3}

User Mihai Marinescu
by
8.2k points

1 Answer

1 vote
The answer to your equation is
5(y-3)/2
Hope this helps.
User Michael Hunger
by
8.1k points
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