Question

34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and what will be left over

Answer 1

11 molecules of CH4.

23 atoms of C is the leftover.

Step-by-step explanation:

Hello!

In this case, for the formation of methane:

`C+2H_2\rightarrow CH_4`

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

`molecules _(H_2)=34atomC*(2molec\ H_2)/(1atomC) =68molec\ H_2`

Thus, the formed molecules of methane are computed below:

`molec\ CH_4=22molec\ H_2 *(1molec\ CH_4)/(2molmolec\ H_2) \\\\molec\ CH_4=11molec\ CH_4`

In such a way, the leftover of carbon atoms are:

`atoms \ C^(left over)=34-22molec\ H_2*(1atoms C)/(2molec\ H_2) \\\\atoms \ C^(left over)=23 atoms C`

Best regards!