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PLEASE HELP I NEED YOUR HELP GUYS PLEASE !

PLEASE HELP I NEED YOUR HELP GUYS PLEASE !-example-1

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First, establish the amount of marbles in the jar, and the amount of marbles that belong to each color.

16 total marbles
4 red marbles
7 blue marbles
5 green marbles

a. The probability of selecting a red marble is as follows:

(red marbles / total amount of marbles)

The same will go for blue and green.

When you are finding out the probability of performing a sequence of events, you multiply the individual probabilities of each event occurring.


Find the probability of pulling a red marble.

4 red marbles / 16 total marbles = 4/16 chance of pulling a red marble

You are replacing the marble afterwards, so the total amount of marbles do not change.

Find the probability of pulling a blue marble.

7 blue marbles / 16 total marbles = 7/16 chance of pulling a blue marble

Multiply these probabilities together.


(4)/(16) * (7)/(16) = (28)/(256) = (7)/(64)

There is a 7/64 chance of pulling a red marble, replacing it, then pulling a blue marble afterwards.

b.

Find the probability of pulling a red marble.

4 red marbles / 16 total marbles = 4/16 chance of pulling a red marble

You are setting the marble outside the jar, so subtract 1 from the total amount of marbles. You now have 15 marbles in the jar.

Find the probability of pulling a blue marble.

7 blue marbles / 15 total marbles = 7/15 chance of pulling a blue marble

Multiply these two probabilities together.


(4)/(16) * (7)/(15) = (28)/(240) = (7)/(60)

There is a 7/60 chance of pulling a red marble, setting it aside, then pulling a blue marble.

c.

The answers are different because the total amount of marbles changed in b, while the total amount did not change in a.
User Frmbelz
by
8.2k points
7 votes
Total = 16 marbles
R = 4
B = 7
G = 5

a)
P(R) = 4/17
with replacing it P(B) = 7/17
so
P(R, then B) = 4/17 x 7/17 = 28/289

b)
P(R) = 4/17
no replacing, P(B) = 7/16
so
P(R, then B) = 4/17 x 6/17 = 24/289

c)
The answers to parts a and b are not the same.
Part a (28/289) with replacing, the probability to select a red then blue is higher then part b (24/289)
User Carlos Negron
by
7.3k points

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