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Q7 Q26.) Find the quotient of the complex numbers and leave your answer in polar form.

Q7 Q26.) Find the quotient of the complex numbers and leave your answer in polar form-example-1
User Snobojohan
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For any complex numbers in polar form
c_1 = r_1\text{cis}(\theta_1),\ c_2 = r_2\text{cis}(\theta_2)

(Where
\text{cis}(\theta) = \cos(\theta) + i\sin(\theta))

Then
(c_1)/(c_2) = (r_1)/(r_2)\text{cis}(\theta_1-\theta_2)

So then for your problem, that would be


(z_1)/(z_2) = \frac37\text{cis}\left(\frac\pi8-\frac\pi9\right)=\boxed{\frac37\text{cis}\left(\frac\pi{72}\right)}

So that would be
\boxed{\frac37\left(\cos\left(\frac\pi{72}\right)+i\sin\left(\frac\pi{72}\right)\right)}

Hope this helps.
User Ddoman
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