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3 votes
Solve
1. 3√5c*7√15c^2
please show your work

1 Answer

6 votes
let √ be a square root

3√(5c)×7√(15c²)

1. take out the c² from√

3√(5c)×7c√15

2.multiply the coefficients and √, also use the √ rule of using single√.

21c√(5c×15)

3. and 4. get 25 of the √.

21c√(25×3c)

21×5c√(3c)

5. multiply the coefficients

105c√(3c)
User Romancha KC
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