Question

ANSWER ASAP

The specific heat of aluminum is 0.125 cal/g °C. If 12.5 grams of aluminum were heated from 20.0 °C to 100.0 °C, ____ calories of heat energy would be absorbed by the aluminum.

INTEGRATED PHYSICS AND CHEMISTRY

Answer 1

125 is your answer.

Step-by-step explanation:

Answer 2

The amount of heat needed to increase the temperature of a substance by
`\Delta T` is given by

`Q=mC_s \Delta T`
where
m is the mass of the substance
Cs is the specific heat capacity of the substance

`\Delta T` is the increase of temperature of the substance

If we plug the data of the problem into the formula, we find

`Q=(12.5 g)(0.125 cal/g^(\circ)C)(100.0^(\circ)C-20.0^(\circ)C)=125 cal`
and this is the amount of heat needed to bring 12.5 g of aluminium from 20 degrees to 100 degrees.