Question

Solve by factoring AKA zero product property method. If the equation has no real solutions, write no real solutions.

3. x^2 − 5 + 4 = 0
4. x^2 + 7 + 12 = 0

Answer 1

Hello,


`1)\\ x^2-5x+4=0\\ x^2-4x-x+4=0\\ x(x-4)-(x-4)=0\\ (x-4)(x-1)=0\\ Sol=\{1;4\}\\\\ 2)\\ x^2+7x+12=0\\ x^2+3x+4x+12=0\\ x(x+3)+4(x+3)=0\\ (x+3)(x+4)=0\\ Sol=\{-4;-3\}`