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Three tension forces OA, OB and OC are equal in magnitude and magnitude of their summation is 200 N. What is the magnitude of each force

User AntPachon
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2 Answers

3 votes

Final answer:

Each of the three equal magnitude tension forces (OA, OB, and OC) that sum to a resultant force of 200 N must individually have magnitudes of 200 N due to the principles of vector addition and symmetry.

Step-by-step explanation:

The question asks for the magnitude of each tension force (OA, OB, and OC) given that all three are equal in magnitude, and their vector sum is 200 N. In physics, these forces are considered vectors and their equal magnitude suggests symmetry. Since the resultant force is the vector sum of all individual forces, and the sum's magnitude is given as 200 N, the individual forces must be directed in such a way that their combined effect results in this net force.

To solve this, one must consider the system's geometry or use a vector addition approach. However, the question doesn't provide the angles at which the forces act. In a common case where the three forces are pulling at the corners of an equilateral triangle, we can use vector addition and trigonometry principles to determine each force's magnitude. Due to symmetry and given that the three forces have an equal magnitude, the result is that each force has a magnitude of 200 N.

User Awefsome
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3.0k points
4 votes

Answer:

The magnitude of each force is 66.67 N

Step-by-step explanation:

Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;

|OA| = |OB| = |OC| = x

Since their summation = 200 N, then;

|OA| + |OB| + |OC| = 200

This implies that;

x + x + x = 200

3x = 200

x =
(200)/(3)

= 66.6667

x = 66.67 N

Therefore, the magnitude of each tension force is approximately 66.67 N

User AndreyICE
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3.3k points