we know that
The measure of the external angle is the semi difference of the arcs that it covers.
so
see the picture attached to better understand the problem
m AB=128°--------> by central angle
m ACB=360°-128°-----> m ACB=232°
∠x=(1/2)*[m ACB-m AB]
∠x=(1/2)*[232-128]-----> ∠x=(1/2)*104°-----> ∠x=52°
the answer is
∠ x is 52°