Question

In the laboratory you are asked to make a 0.175 m barium sulfide solution using 15.4 grams of barium sulfide. How much water should you add

Answer 1

0.5195 liters of water

Step-by-step explanation:

First we convert 15.4 grams of barium sulfide (BaS) into moles, using its molar mass:

• 15.4 g ÷ 169.39 g/mol = 0.0909 mol

Then we calculate the required volume of water, using the definition of molarity:

• molarity = moles / volume

• 0.175 M = 0.0909 mol / Volume

• Volume = 0.5195 L