Answer:
The length of BC is 11√2 ft.
Explanation:
Given,
A right angled triangle ABC,
In which,
AC = 11 ft ( By diagram ),
∠A = 90°,
∠B = 45°,
By the law of sine,
![(sin B)/(AC)=(sin A)/(BC)](https://img.qammunity.org/2019/formulas/mathematics/high-school/9vdurnrxicknmhcpavm04jgv4t1sh7omr0.png)
( By cross multiplication )
![\implies BC = (AC* sin A)/(sin B)](https://img.qammunity.org/2019/formulas/mathematics/high-school/dkzpuwmk7slyvoqoo7cf3tvi68pn730cuq.png)
By substituting the values,
![BC=(11* sin 90^(\circ))/(sin 45^(\circ))](https://img.qammunity.org/2019/formulas/mathematics/high-school/q1qd8zb9d91ujdpsp1jihtz6ez7s5fd88a.png)
![=(11)/((1)/(√(2)))](https://img.qammunity.org/2019/formulas/mathematics/high-school/vw0qvngvu17xm9nsd7i2oz6857arexs781.png)
![=11√(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pbf6segiiv85ljndr3z7lm2901job1insh.png)
Hence, the length of BC is 11√2 ft.