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Inverse Trigonometry solve the questions below

Inverse Trigonometry solve the questions below-example-1
User Cademan
by
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1 Answer

5 votes

Answer:

1. θ = 34.85°

2. x = 36.31°

3. x = 39.80°

Explanation:

1. Determination of θ.

Adjacent = 11.9

Hypothenus = 14.5

Angle θ =?

Cos θ = Adjacent /Hypothenus

Cos θ = 11.9 / 14.5

Cos θ = 0.8207

Take the inverse of Cos

θ = Cos¯¹ 0.8207

θ = 34.85°

2. Determination of x

Opposite = 9 m

Hypothenus = 15.2 m

Angle x =?

Sine x = Opposite /Hypothenus

Sine x = 9 / 15.2

Sine x = 0.5921

Take the inverse of Sine

x = Sine¯¹ 0.5921

x = 36.31°

3. Determination of x

Opposite = 10 in

Adjacent = 12 in

Angle x =?

Tan x = Opposite / Adjacent

Tan x = 10 / 12

Tan x = 0.8333

Take the inverse of Tan

x = Tan¯¹ 0.8333

x = 39.80°

User Durul Dalkanat
by
5.5k points