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Find the center, vertices, and foci of the ellipse with equation 2x2 + 9y2 = 18.

User Woran
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1 Answer

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To solve this problem you must apply the proccedure showb below:

1. You have the following equation:

2x^2+9y^2=18

2. Dividing the equation by 18, you have:

(x^2/9)+(y^2/2)=1

3. The center is:

[(x-0)^2/9]3^2[(y-0)^2/√2]=1

(h,k)=(0,0)

The center is (0,0)

4. The vertices are:

a^2=9
a=3

Vertices: (-3,0) and (3,0)

5. The foci is:

c^2=a^2-b^2
c=
√7

The foci is: (-
√7,0) and (√7,0)
User Alyss
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