Newton's second law gives the relationship between force applied to an object, its mass and its acceleration:
![F=ma](https://img.qammunity.org/2019/formulas/physics/middle-school/1fz9hgmj558w2aylxf067s9vb6qwkf1pat.png)
where F is the force, m the mass and a the acceleration.
A force F is applied to football A, whose mass is
![m_A](https://img.qammunity.org/2019/formulas/physics/middle-school/g1y8h2z15hr1cj3dwib3ymdslmxevw4v3x.png)
, and so the acceleration of this football will be given by (re-arranging the previous equation)
![a_A = (F)/(m_A)](https://img.qammunity.org/2019/formulas/physics/middle-school/sfm2u2yiukrmi6mk2wgy2sh51222uyr7yq.png)
Similarly, the acceleration of football B will be
![a_B= (F)/(m_B)](https://img.qammunity.org/2019/formulas/physics/middle-school/7o5idmtxae4y7gyl1ru1mtsreb5jkd6l77.png)
where
![m_B](https://img.qammunity.org/2019/formulas/physics/middle-school/vclhog05pyfqk7s4ytt1p0ahs3nh86dyyv.png)
is the mass of football B, and where the force F applied to the two footballs is the same.
Since football A has greater mass than football B,
![m_A \ \textgreater \ m_B](https://img.qammunity.org/2019/formulas/physics/middle-school/hmuodnke0adhp7a4eyqgb1t16utdehv3ff.png)
, if we compare the two previous formula we see that the acceleration of football B is greater than the acceleration of football A:
![a_B \ \textgreater \ a_A](https://img.qammunity.org/2019/formulas/physics/middle-school/7gng1hofu4mcgbcp8ldxgue0mzqgrbe76u.png)
Therefore, if the same force is applied to the two footballs, football B will accelerate more than football A.