Question

The osmotic pressure of a solution formed by dissolving 45.0 mg of aspirin (c9h8o4) in enough water to make 0.250 l of solution at 25°c is ________ atm

Answer 1

The osmotic pressure of the solution can be calculated using the formula Π = MRT. First, convert the mass of aspirin to moles, then calculate the molarity by dividing the moles by the volume. Finally, calculate the osmotic pressure using the molarity, ideal gas constant, and temperature.

Step-by-step explanation:

The osmotic pressure of a solution can be calculated using the formula:

Π = MRT

Where Π is the osmotic pressure, M is the molarity of the solution, R is the ideal gas constant, and T is the temperature in Kelvin.

In this case, we are given the mass of aspirin and need to calculate the molarity to determine the osmotic pressure.

First, we need to convert the mass of aspirin to moles:

45.0 mg x (1 g/1000 mg) x (1 mol/180.16 g) = 0.000249 mol

Next, we need to calculate the molarity:

M = moles/volume = 0.000249 mol/0.250 L = 0.000996 M

Finally, we can calculate the osmotic pressure:

Π = (0.000996 M)(0.0821 L. atm/mol. K)(298 K) = 0.0246 atm

Answer 2

Answer is: osmotic pressure of aspirin is 0.025 atm.
m(C₉H₈O₄) = 45.0 ÷ 1000 mg/g = 0.045 g.
n(C₉H₈O₄) = m(C₉H₈O₄) ÷ M(C₉H₈O₄).
n(C₉H₈O₄) = 0.045 g ÷ 180 g/mol.
n(C₉H₈O₄) = 0.00025 mol.
c(C₉H₈O₄) = n(C₉H₈O₄) ÷ V(solution).
c(C₉H₈O₄) = 0.00025 mol ÷ 0.25 L.
c(C₉H₈O₄) = 0.001 M.
T = 25°C = 298.15 K.
R = 0.08206 L·atm/mol·K, universal gas constant.
p = c · R · T.
p = 0.001 mol/L · 0.08206 L·atm/mol·K · 298.15 K.
p = 0.025 atm.